breaking-in headphones?

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Phil O
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Post by Phil O »

FYI

The gain is going to be 20Log[70/(70+R)] where 70 is the resistance (actually impedance) of your headphones and R is the series resistor.

So for a 70 ohm series resistor: 20Log(0.5)= -6.02 db.

A bigger resistor will give you more attenuation.

Sorry, it's late, just babbling.

Phil
DP 11.34. 2020 M1 Mac Mini [9,1] (16 Gig RAM), Mac Pro 3GHz 8 core [6,1] (16 Gig RAM), OS 15.3/11.6.2, Lynx Aurora (n) 8tb, MOTU 8pre-es, MOTU M6, MOTU 828, Apogee Rosetta 800, UAD-2 Satellite, a truckload of outboard gear and plug-ins, and a partridge in a pear tree.
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monkey man
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Post by monkey man »

That's good babble, Phil; thank you. :D

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